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March 29
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Lyra's calification by Pandramodo Lyra's calification by Pandramodo
:iconlyraponyplz::iconsaysplz:problem? :iconhiddentrollfaceplz:
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:iconbluefoxycat:
bluefoxycat Featured By Owner Aug 16, 2014  Student Artist
Whooves' face. That's all, folks.
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:icondragonfua11:
DragonFUA11 Featured By Owner Aug 7, 2014  New member
.... -R!
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:iconstargazerdesign:
StargazerDesign Featured By Owner Jul 25, 2014  Student Interface Designer
Math is complicated... 
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:iconleapingpony:
LeapingPony Featured By Owner Jul 29, 2014  New member Hobbyist Digital Artist
Ohh, if think is SO Complicated.. Then Answer These Questions.... (U Can Say IDK I Don't Know If Want To)

79 + 51 - reciproc(86) = ????

sqrt (915) = ??????

See? easy.... :3
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:iconstargazerdesign:
StargazerDesign Featured By Owner Jul 29, 2014  Student Interface Designer
Thank you for the explanation, but I REALLY hate math. ;D
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:iconleapingpony:
LeapingPony Featured By Owner Jul 31, 2014  New member Hobbyist Digital Artist
Okay... :P
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:iconcooper31:
Cooper31 Featured By Owner Jul 25, 2014  New member Student Digital Artist
Exploding maths problem!
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:iconspeedy526745:
Speedy526745 Featured By Owner Jul 24, 2014  Hobbyist Digital Artist
Is it bad that I immediately tried to solve this equation as soon as I saw it?

And here's the breakdown, because that's how I roll:
x + sqrt(x - 1) = 2x – 7

sqrt(x - 1) = x – 7

x – 1 = (x - 7)2 = x2 – 14x + 49

0 = x2 – 15x + 50

0 = (x – 5)(x – 10)

7 ≠ 3, so x ≠ 5

13 = 13, so x = 10  

 

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:iconpandfstudios:
PandFStudios Featured By Owner Edited 3 days ago  Hobbyist Digital Artist
You're not the only one...
I tried to square both sides immediately and got stuck at

3/2x-29/2+24/x = √(x+1)...

Haven't math-ed in a while...

Btw I think you're probably right.

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:iconthepianistdragon:
ThePianistDragon Featured By Owner Jul 25, 2014  Hobbyist Traditional Artist

I did mine a little differently.
X + √(X-1) = 2X - 7  the equation on the card

√(X-1) = X - 7   getting the sqrt by itself

X – 1 ≥ 0    calculating what the x under the sqrt could be

X ≥ 1    done; the x under the sqrt has to be greater than or equal to 1

0 ≥ X – 7    knowing the end result of the sqrt has to be greater than or equal to zero we use this to calculate what x by itself should be

7 ≥ X    done; the score on the card has to be seven or more (but nothing more than 10)

X – 1 = (X - 7) * (X - 1)    multiplying both sides by  removes the sqrt

X = 7 , X ≠ 1    we already know x by itself can't be 1, so it has to be 7

X – 1 = 7    but we still have a minus one on the other side, so…

X = 8    that's better


I haven't done this sort of math in a while, so I'm not sure if I'm right. But I just wanted to show how I got it. I got 8 as my score.

 

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